passpadi

2023

Mathematics

JAMB

A boat sails 8 km north from P to Q and then sails 6 km west from Q to R. Calculate the bearing of R from P. Give your answer to the nearest degree.

A.

217o

B.

323o

C.

037o

D.

053o

Correct Answer: 323o

Explanation

tan θ = opp/adj = RQ/QP = 6/8 tan θ = 0.75 θ = tan−1(0.75) = 36.87° ∴ The bearing of R from P = 360° - 36.87° = 323° (to the nearest degree)

tan θ = opp/adj = RQ/QP = 6/8 tan θ = 0.75 θ = tan−1(0.75) = 36.87° ∴ The bearing of R from P = 360° - 36.87° = 323° (to the nearest degree)
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