2005
Mathematics
67ca00ce0c643c71d77dee1f
Evaluate ∫0, (π/2sin2xdx
A.
1
B.
Zero
C.
-1/2
D.
-1
Correct Answer: 1
Explanation
∫0(π/2sin2xdxx = [-1/2cos 2x + C](π/20 =[-1/2 cos 2 * π/2 + C] - [-1/2 cos 2 * 0] = [-1/2 cos π] - [-1/2 cos 0] = [-1/2x - 1] - [-1/2 * 1] = 1/2 -(-1/2) = 1/2 + 1/2 = 1
∫0(π/2sin2xdxx = [-1/2cos 2x + C](π/20 =[-1/2 cos 2 * π/2 + C] - [-1/2 cos 2 * 0] = [-1/2 cos π] - [-1/2 cos 0] = [-1/2x - 1] - [-1/2 * 1] = 1/2 -(-1/2) = 1/2 + 1/2 = 1THIS WEEK's
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