passpadi

2005

Mathematics

JAMB

Evaluate ∫0, (π/2sin2xdx

A.

1

B.

Zero

C.

-1/2

D.

-1

Correct Answer: 1

Explanation

0(π/2sin2xdxx = [-1/2cos 2x + C](π/20 =[-1/2 cos 2 * π/2 + C] - [-1/2 cos 2 * 0] = [-1/2 cos π] - [-1/2 cos 0] = [-1/2x - 1] - [-1/2 * 1] = 1/2 -(-1/2) = 1/2 + 1/2 = 1

0(π/2sin2xdxx = [-1/2cos 2x + C](π/20 =[-1/2 cos 2 * π/2 + C] - [-1/2 cos 2 * 0] = [-1/2 cos π] - [-1/2 cos 0] = [-1/2x - 1] - [-1/2 * 1] = 1/2 -(-1/2) = 1/2 + 1/2 = 1
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