passpadi

2005

Mathematics

JAMB

The sum of the interior angle of a regular polygon is 1800o. Calculate the size of one exterior angle of the polygon

A.

30°

B.

24°

C.

18°

D.

12°

Correct Answer: 30°

Explanation

Sum of interior ∠s = 1800° ∴(n - 2) 180° = 1800° 180n -360° = 1800° 180n = 1800° + 360° 180n = 2160° n = 2160°/180° n = 12 sides Each exterior ∠ = 360°/n = 360°/12 = 30°

Sum of interior ∠s = 1800° ∴(n - 2) 180° = 1800° 180n -360° = 1800° 180n = 1800° + 360° 180n = 2160° n = 2160°/180° n = 12 sides Each exterior ∠ = 360°/n = 360°/12 = 30°
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