passpadi

2005

Mathematics

JAMB

If the interest on N150.00 for 2(1/2) years is N4.50, find the interest on N250.00 for 6 months at the same rate

A.

N1.50

B.

N7.50

C.

N15.00

D.

N18.00

Correct Answer: N1.50

Explanation

I=N4.50,P=N150,T=2 1/2 years. I = (P×T×R)/100. 4.50= (150 × 2 (1/2) × R ) /100 4.50/1=(150 × 5 × R)/(100 × 2). 4.50× 4 = 15R. R = (4.50 × 5)/15. R =6/5 Again I = (P × T × R)/100=(250 × 1 × 6)/(100 × 2 ×5). = 3/2=N1.50

I=N4.50,P=N150,T=2 1/2 years. I = (P×T×R)/100. 4.50= (150 × 2 (1/2) × R ) /100 4.50/1=(150 × 5 × R)/(100 × 2). 4.50× 4 = 15R. R = (4.50 × 5)/15. R =6/5 Again I = (P × T × R)/100=(250 × 1 × 6)/(100 × 2 ×5). = 3/2=N1.50
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