2005
Mathematics
JAMB
Three straight lines EF, GH and LK interest at O as shown above. If ∠KOF = 52° and ∠LOH = 85°, calculate the size of ∠EOG.
A.
26°
B.
43°
C.
52°
D.
85°
Correct Answer: 43°
Explanation
∠GOK = 85° (vertical opposite angle ∠s) ∠EOG + ∠GOK + ∠KOF = 180 (∠s on a straight line) ∠EOg + 85° + 52° = 180° ∠EOG + 137° = 180° ∠EOG = 43°
∠GOK = 85° (vertical opposite angle ∠s) ∠EOG + ∠GOK + ∠KOF = 180 (∠s on a straight line) ∠EOg + 85° + 52° = 180° ∠EOG + 137° = 180° ∠EOG = 43°THIS WEEK's
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