2005
Mathematics
JAMB
What is the probability that an integer x,(1 ≤ x ≤ 20) chosen at random is divisible by both 2 and 3?
A.
1/20
B.
1/3
C.
3/20
D.
7/10
Correct Answer: 3/20
Explanation
U = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20} A = {x/x is divisible by 2} A = {2,4,6,8,10,12,14,16,18,20} B = {x/x is divisible by 3} A ∩ B = {6, 12, 18} P(Number divisible by both 2 and 3) = 3/20
U = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20} A = {x/x is divisible by 2} A = {2,4,6,8,10,12,14,16,18,20} B = {x/x is divisible by 3} A ∩ B = {6, 12, 18} P(Number divisible by both 2 and 3) = 3/20THIS WEEK's
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