passpadi

2005

Mathematics

JAMB

In the diagram above calculate the value of x

A.

60°

B.

100°

C.

120°

D.

140°

Correct Answer: 120°

Explanation

p + 40° = 100° (exterior ∠ = sum of two interior opp ∠s) p = 100° - 40° P = 60° But q + p = 180° (∠s on a straight line) q + 60° q = 180° - 60° q = 120° x = q (corresponding ∠) ∴x = 120°

p + 40° = 100° (exterior ∠ = sum of two interior opp ∠s) p = 100° - 40° P = 60° But q + p = 180° (∠s on a straight line) q + 60° q = 180° - 60° q = 120° x = q (corresponding ∠) ∴x = 120°
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