2019
Mathematics
67ca00ce0c643c71d77dee1f
Integrate ∫(-1)2(2x2 + x)dx
A.
4(1/2)
B.
3(1/2)
C.
7(1/2)
D.
5(1/24)
Correct Answer: 7(1/2)
Explanation
∫(-1)2(2x2 + x)dx = [(2x(2+1))/3+x(1+1)/2 ](-1)2 = [(2x3)/3 + x2/2 ](-1)2 = ((2(2)3 )/3+22 2 ) -((2(-1)3 )/3+((-1)+M312 )/2) = (16/3+2)-((-2)/3+1/2) = 22/3-(-1/6) = 22/3 + 1/6 = 7(1/2)
∫(-1)2(2x2 + x)dx = [(2x(2+1))/3+x(1+1)/2 ](-1)2 = [(2x3)/3 + x2/2 ](-1)2 = ((2(2)3 )/3+22 2 ) -((2(-1)3 )/3+((-1)+M312 )/2) = (16/3+2)-((-2)/3+1/2) = 22/3-(-1/6) = 22/3 + 1/6 = 7(1/2)THIS WEEK's
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