2019
Mathematics
67ca00ce0c643c71d77dee1f
If 4sin2x−3=0, find the value of x, when 0° ≤ x ≤ 90°
A.
90°
B.
45°
C.
60°
D.
30°
Correct Answer: 60°
Explanation
4sin2x − 3 = 0 4sin2x = 3 ⟹ sin2x = 3/4 sin x = √3/2 ∴ x = sin−1(√3/2) x = 60°
4sin2x − 3 = 0 4sin2x = 3 ⟹ sin2x = 3/4 sin x = √3/2 ∴ x = sin−1(√3/2) x = 60°THIS WEEK's
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