passpadi

2019

Mathematics

JAMB

Points X and Y are 20km North and 9km East of point O, respectively. What is the bearing of Y from X? Correct to the nearest degree.

A.

24°

B.

56°

C.

127°

D.

156°

Correct Answer: 156°

Explanation

tanθ = 9/20 = 0.45 θ = tan(−1)(0.45) = 24.23° ∴ The bearing of Y from X = 180° - 24.23° = 155.77° = 156° (to the nearest degree)

tanθ = 9/20 = 0.45 θ = tan(−1)(0.45) = 24.23° ∴ The bearing of Y from X = 180° - 24.23° = 155.77° = 156° (to the nearest degree)
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