2018
Mathematics
JAMB
A trader realises 10x - x2 Naira profit from the sale of x bags of corn. How many bags will give him the maximum profit?
A.
7
B.
6
C.
5
D.
4
Correct Answer: 5
Explanation
Profit (P) = 10x − x2 Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0 i.e. dp/dx = 0 dp/dx = 10 - 2x = 0 10 = 2x Then x = 10/2 = 5
Profit (P) = 10x − x2 Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0 i.e. dp/dx = 0 dp/dx = 10 - 2x = 0 10 = 2x Then x = 10/2 = 5THIS WEEK's
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