2017
Mathematics
67ca00ce0c643c71d77dee1f
If two graphs Y = px2 + q and y = 2x2 − 1 intersect at x =2, find the value of p in terms of q
A.
q − 8/7
B.
7 − q/4
C.
8 − q/2
D.
7 + q/8
Correct Answer: 7 − q/4
Explanation
Y = Px2 + q Y = 2x2 - 1 Px2 + q = 2x2 - 1 Px2 = 2x2 - 1 - q p = (2x2−1−q)/x2 at x = 2 P = (2(2)2−1−q)/22 = (2(4)−1−q)/4 = (8−1−q)/4 P = (7−q)/4
Y = Px2 + q Y = 2x2 - 1 Px2 + q = 2x2 - 1 Px2 = 2x2 - 1 - q p = (2x2−1−q)/x2 at x = 2 P = (2(2)2−1−q)/22 = (2(4)−1−q)/4 = (8−1−q)/4 P = (7−q)/4THIS WEEK's
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