2017
Mathematics
67ca00ce0c643c71d77dee1f
Find ∫(x2 + 3x − 5)dx
A.
x3/3 - 3x2/2 - 5x + k
B.
x3/3 - 3x2/2 + 5x + k
C.
x3/3 + 3x2/2 - 5x + k
D.
x3/3 + 3x2/2 + 5x + k
Correct Answer: x3/3 + 3x2/2 - 5x + k
Explanation
∫xndx = xn+1/n+1 ∫dx = x + k where k is constant ∫(x2 + 3x − 5)dx ∫x2 dx + ∫3xdx − ∫5dx (22 + 1)/(2 + 1) + 3x1+1/(1+1) − 5x + k x3/3 + 3x2/2 − 5x + k
∫xndx = xn+1/n+1 ∫dx = x + k where k is constant ∫(x2 + 3x − 5)dx ∫x2 dx + ∫3xdx − ∫5dx (22 + 1)/(2 + 1) + 3x1+1/(1+1) − 5x + k x3/3 + 3x2/2 − 5x + kTHIS WEEK's
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