passpadi

2016

Mathematics

JAMB

In the diagram above, l1 is parallel to l2, Find the value of < PMT

A.

82°

B.

36°

C.

72°

D.

118°

Correct Answer: 82°

Explanation

< MPT = 180° - 118° = 62° < PML = 62° ( Alternative angle) y + 2y + 10° + 62° = 180° (Angles on a straight line) 3y = 180 - 72 3y/3 = 108/3 y = 36° < PMT = 2y + 10 = 2(36) + 10 = 82°

< MPT = 180° - 118° = 62° < PML = 62° ( Alternative angle) y + 2y + 10° + 62° = 180° (Angles on a straight line) 3y = 180 - 72 3y/3 = 108/3 y = 36° < PMT = 2y + 10 = 2(36) + 10 = 82°
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