2016
Mathematics
67ca00ce0c643c71d77dee1f
Evaluate ∫0π/2 sin xdx
A.
2
B.
-1
C.
1
D.
-2
Correct Answer: 1
Explanation
Evaluate ∫0π/2 sin xdx = -cosx|π/2 = -(cosπ/2 - cos0) = -(0-1) = 1
Evaluate ∫0π/2 sin xdx = -cosx|π/2 = -(cosπ/2 - cos0) = -(0-1) = 1THIS WEEK's
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