Find the equation of a line which is form origin and passes through the point (−3, −4)
A.
y = 3x/4
B.
y = 4x/3
C.
y = 2x/3
D.
y = x/2
Correct Answer: y = 4x/3
Explanation
The slope of the line from (0, 0) passing through (-3, -4) = (−4−0)/(−3−0) = 4/3
Equation of a line is given as y=mx+b, where m = slope and b = intercept.
To get the value of b, we use a point on the line, say (0, 0).
y=4/3x+b
0=4/3(0)+b
b = 0
The equation of the line is y = 4/3x
The slope of the line from (0, 0) passing through (-3, -4) = (−4−0)/(−3−0) = 4/3
Equation of a line is given as y=mx+b, where m = slope and b = intercept.
To get the value of b, we use a point on the line, say (0, 0).
y=4/3x+b
0=4/3(0)+b
b = 0
The equation of the line is y = 4/3x
