Using the quadratic formula, we have
x=−b±√(b2 −4ac)/2a
From the equation 3x2−4x−5 = 0, a = 3, b = -4 and c = -5.
∴x=−(−4)±√((−4)2−4(3)(−5))/2(3)
= 4±√(16+60)/6
= 4±√(76)/6
= 4±8.72/6
= 4+8.72/6 or 4−8.72/6
= 12.72/6 or −4.72/6
x = 2.12 or -0.79
Using the quadratic formula, we have
x=−b±√(b2 −4ac)/2a
From the equation 3x2−4x−5 = 0, a = 3, b = -4 and c = -5.
∴x=−(−4)±√((−4)2−4(3)(−5))/2(3)
= 4±√(16+60)/6
= 4±√(76)/6
= 4±8.72/6
= 4+8.72/6 or 4−8.72/6
= 12.72/6 or −4.72/6
x = 2.12 or -0.79