passpadi

2015

Mathematics

JAMB

Simplify [1÷(x2 + 3x + 2)]+[1 ÷ (x2 + 5x + 6)]

A.

2/(x+1)2

B.

2/(x+1)(x+2)

C.

2(x+1)(x+2)

D.

2(x+1)(x+3)

Correct Answer: 2(x+1)(x+3)

Explanation

[1÷(x2 + 3x +2)] + [1 ÷ (x2 + 5x + 6)] = 1 ÷ (x2 + 3x + 2) + [1 ÷ (x2 + 5x + 6)] = [1 ÷ ((x2 + x) + (2x + 2))] + [1 ÷ ((x2 + 3x) + (2x + 6))] = [1 ÷ (x(x + 2) + 2(x +1))] + [1 ÷ (x(x + 3) +2(x + 3) )] = [1 ÷ (x + 1)(x + 2)] + [1 ÷ ((x + 3) + (x + 2))] =((x + 3) + (x + 1)) ÷ (x + 1)(x + 2)(x + 3) Using the L.C.M =((x + x + 3 + 1)) ÷ (x + 1)(x + 2)(x + 3) =(2x+4)/(x+1)(x+2)(x+3) =2(x+2)/(x+1)(x+2)(x+3) = 2/(x+1)(x+3)

[1÷(x2 + 3x +2)] + [1 ÷ (x2 + 5x + 6)] = 1 ÷ (x2 + 3x + 2) + [1 ÷ (x2 + 5x + 6)] = [1 ÷ ((x2 + x) + (2x + 2))] + [1 ÷ ((x2 + 3x) + (2x + 6))] = [1 ÷ (x(x + 2) + 2(x +1))] + [1 ÷ (x(x + 3) +2(x + 3) )] = [1 ÷ (x + 1)(x + 2)] + [1 ÷ ((x + 3) + (x + 2))] =((x + 3) + (x + 1)) ÷ (x + 1)(x + 2)(x + 3) Using the L.C.M =((x + x + 3 + 1)) ÷ (x + 1)(x + 2)(x + 3) =(2x+4)/(x+1)(x+2)(x+3) =2(x+2)/(x+1)(x+2)(x+3) = 2/(x+1)(x+3)
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