passpadi

2014

Mathematics

JAMB

Evaluate ∫sin2xdx

A.

cos 2x + k

B.

1/2cos 2x + k

C.

−1/2 cos 2x + k

D.

-cos 2x + k

Correct Answer: −1/2 cos 2x + k

Explanation

∫sin2xdx =1/2(−cos2x) + k −1/2cos2x + k

∫sin2xdx =1/2(−cos2x) + k −1/2cos2x + k
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