2014
Mathematics
JAMB
in the figure above, what is the equation of the line that passes the y-axis at (0,5) and passes the x-axis at (5,0)?
A.
y = x + 5
B.
y = -x + 5
C.
y = x - 5
D.
y = -x - 5
Correct Answer: y = -x + 5
Explanation
(x1 , y1 ) = (0,5) (x2 , y2 ) = (5, 0) Using (y − y12 − y1) = (x − x1)/(x2 − x1) (y−5)/(0−5) = (x−0)/(5−0) (y−5)/−5 = x/5 5(y - 5) = -5x y - 5 = -x x + y = 5 y = -x + 5
(x1 , y1 ) = (0,5) (x2 , y2 ) = (5, 0) Using (y − y12 − y1) = (x − x1)/(x2 − x1) (y−5)/(0−5) = (x−0)/(5−0) (y−5)/−5 = x/5 5(y - 5) = -5x y - 5 = -x x + y = 5 y = -x + 5THIS WEEK's
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