2014
Mathematics
JAMB
Evaluate ∫(2x+3)(1/2) δx
A.
1/12(2x+3)6 +k
B.
1/3(2x+3)(1/2) +k
C.
1/3(2x+3)3/2 +k
D.
1/12(2x+3)3/4 +k
Correct Answer: 1/3(2x+3)3/2 +k
Explanation
∫(2x + 3)(1/2)δx let u = 2x + 3, δy/δx=2 δx=δu/2 Now ∫(2x+3)(1/2)δx=∫u(1/2).δx/2 =1/2∫u(1/2)δu =1/2u(3/2)×23 + k =1/3u(3/2) + k =1/3(2x+3)3/2 + k
∫(2x + 3)(1/2)δx let u = 2x + 3, δy/δx=2 δx=δu/2 Now ∫(2x+3)(1/2)δx=∫u(1/2).δx/2 =1/2∫u(1/2)δu =1/2u(3/2)×23 + k =1/3u(3/2) + k =1/3(2x+3)3/2 + kTHIS WEEK's
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