2013
Mathematics
JAMB
A chord of a circle subtends an angle of 120° at the centre of a circle of diameter 4√3cm . Calculate the area of the major sector.
A.
32πcm2
B.
4π cm2
C.
8π cm2
D.
16π cm2
Correct Answer: 8π cm2
Explanation
Angle of major sector = 360° - 120° = 240° Area of major sector : θ/360 × πr2 r = 4√3/2 = 2√3cm Area : 240/360× π × (2√3)2 = 8πcm2
Angle of major sector = 360° - 120° = 240° Area of major sector : θ/360 × πr2 r = 4√3/2 = 2√3cm Area : 240/360× π × (2√3)2 = 8πcm2THIS WEEK's
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