2013
Mathematics
JAMB
If S = √(t2-4t+4), find t in terms of s
A.
S2 - 2
B.
S + 2
C.
S - 2
D.
S2 + 2
Correct Answer: S + 2
Explanation
S = √(t2 −4t + 4) S2 = t2 - 4t + 4 t2 - 4t + 4 - S2 = 0 Using t = −b ± √(b22 −4(1)(4−S2/2(1) t = 4 ±√(16−4(4−S2)/2 t = 4 ±√(16−16+4S2/2 t = 4 ±√(4S2/2 t = 2(2±S)/2 Hence t = 2 + S or t = 2 - S
S = √(t2 −4t + 4) S2 = t2 - 4t + 4 t2 - 4t + 4 - S2 = 0 Using t = −b ± √(b22 −4(1)(4−S2/2(1) t = 4 ±√(16−4(4−S2)/2 t = 4 ±√(16−16+4S2/2 t = 4 ±√(4S2/2 t = 2(2±S)/2 Hence t = 2 + S or t = 2 - STHIS WEEK's
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