2012
Mathematics
67ca00ce0c643c71d77dee1f
Evaluate ∫2 1 (x2 −4x)dx
A.
11/3
B.
3/11
C.
-3/11
D.
-11/3
Correct Answer: -11/3
Explanation
∫2 1 (x2 −4x)dx (x3/3 − 4x2/2) substituting integrate values [8/3 − 4 × 4/2] − [1/2 − 2] = −11/3
∫2 1 (x2 −4x)dx (x3/3 − 4x2/2) substituting integrate values [8/3 − 4 × 4/2] − [1/2 − 2] = −11/3THIS WEEK's
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