passpadi

2012

Mathematics

JAMB

If y = x2 - 1/x, find δy/δx

A.

2x - 1/x2

B.

2x + x2

C.

2x - x2

D.

2x + 1x2

Correct Answer: 2x + 1x2

Explanation

y = x2 - 1/x y = x2 - x-1 δy/δx = 2x + x-2 δy/δx = 2x + 1/x2

y = x2 - 1/x y = x2 - x-1 δy/δx = 2x + x-2 δy/δx = 2x + 1/x2
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