2012
Mathematics
JAMB
Evaluate ∫π/4, 0sec2θdθ
A.
1
B.
2
C.
3
D.
4
Correct Answer: 1
Explanation
∫π/4, 0sec2θdθ = [tanθ]π/4, 0 = tanπ/4−tan0 = 1 − 0 = 1.
∫π/4, 0sec2θdθ = [tanθ]π/4, 0 = tanπ/4−tan0 = 1 − 0 = 1.THIS WEEK's
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