passpadi

2012

Mathematics

JAMB

Solve for x and y in the equations below x2 - y2 = 4 x + y = 2

A.

x = 0, y = -2

B.

x = 0, y = 2

C.

x = 2, y = 0

D.

x = -2, y = 0

Correct Answer: x = 2, y = 0

Explanation

x2 - y2 = 4 .... (1) x + y = 2 .... (2) Simplify eqn (1) (x + y)(x - y) = 4 From eqn (2) x + y = 2 so substitute it into simplified eqn (1), we have 2 (x - y) = 4 therefore, x - y = 2 ... (1) x + y = 2 --------- 2x = 4 --------- x = 2, when y = 0

x2 - y2 = 4 .... (1) x + y = 2 .... (2) Simplify eqn (1) (x + y)(x - y) = 4 From eqn (2) x + y = 2 so substitute it into simplified eqn (1), we have 2 (x - y) = 4 therefore, x - y = 2 ... (1) x + y = 2 --------- 2x = 4 --------- x = 2, when y = 0
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