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2011
Mathematics
JAMB
A man walks 100 m due West from a point X to Y, he then walks 100 m due North to a point Z. Find the bearing of X from Z.
A.
195°
B.
135°
C.
225°
D.
045°
Correct Answer:
135°
Explanation
tanθ = 100/100 = 1 θ = tan
-1
(1) = 45° The bearing of x from z is N45oE or 135°
tanθ = 100/100 = 1 θ = tan
-1
(1) = 45° The bearing of x from z is N45oE or 135°
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