passpadi

2011

Mathematics

JAMB

A man walks 100 m due West from a point X to Y, he then walks 100 m due North to a point Z. Find the bearing of X from Z.

A.

195°

B.

135°

C.

225°

D.

045°

Correct Answer: 135°

Explanation

tanθ = 100/100 = 1 θ = tan-1(1) = 45° The bearing of x from z is N45oE or 135°

tanθ = 100/100 = 1 θ = tan-1(1) = 45° The bearing of x from z is N45oE or 135°
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