2011
Mathematics
JAMB
ClassIntervalsFrequency0−233−526−859−113 Find the mode of the above distribution.
A.
9
B.
8
C.
10
D.
7
Correct Answer: 7
Explanation
Mode = L1 + (D11+D2)C D1 = frequency of modal class - frequency of the class before it D1 = 5 - 2 = 3 D2 = frequency of modal class - frequency of the class that offers it D2 = 5 - 3 = 2 L1 = lower class boundary of the modal class L1 = 5 - 5 C is the class width = 8 - 5.5 = 3 Mode = L1 + (D1/D1+D2)C = 5.5 + 3/(2+3)C = 5.5 + 3/5 x 3 = 5.5 + 9/5 = 5.5 + 1.8 = 7.3 ≈ = 7
Mode = L1 + (D11+D2)C D1 = frequency of modal class - frequency of the class before it D1 = 5 - 2 = 3 D2 = frequency of modal class - frequency of the class that offers it D2 = 5 - 3 = 2 L1 = lower class boundary of the modal class L1 = 5 - 5 C is the class width = 8 - 5.5 = 3 Mode = L1 + (D1/D1+D2)C = 5.5 + 3/(2+3)C = 5.5 + 3/5 x 3 = 5.5 + 9/5 = 5.5 + 1.8 = 7.3 ≈ = 7THIS WEEK's
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