2011
Mathematics
JAMB
Find the derivative of sinθ/cosθ
A.
sec2 θ
B.
tan θ cosec θ
C.
cosec θ sec θ
D.
cosec2θ
Correct Answer: sec2 θ
Explanation
sinθ/cosθ. (cosθ (d(sinθ))/dθ - sinθ (d(cosθ))/dθ)/cos2θ. (cosθ.cosθ-sinθ(-sinθ))/(cos2 θ) (cos2 θ+sin2θ)/(cos2 θ) Recall that sin2 θ + cos2 θ = 1 1/cos2θ = sec2 θ
sinθ/cosθ. (cosθ (d(sinθ))/dθ - sinθ (d(cosθ))/dθ)/cos2θ. (cosθ.cosθ-sinθ(-sinθ))/(cos2 θ) (cos2 θ+sin2θ)/(cos2 θ) Recall that sin2 θ + cos2 θ = 1 1/cos2θ = sec2 θTHIS WEEK's
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