2011
Mathematics
JAMB
Find the equation of a line perpendicular to line 2y = 5x + 4 which passes through (4, 2).
A.
5y - 2x -18 = 0
B.
5y + 2x - 18 = 0
C.
5y - 2x + 18 = 0
D.
5y + 2x - 2 = 0
Correct Answer: 5y + 2x - 18 = 0
Explanation
2y = 5x + 4 (4, 2) y = 5x/2 + 4 comparing with y = mx + e m = 5/2 Since they are perpendicular m1m2 = -1 m2 = −1/m1 = -1 5/2 = -1 x 2/5 The equator of the line is thus y = mn + c (4, 2) 2 = -2/5(4) + c 2/1 + 8/5 = c c = 18/5 y = -2/5x + 18/5 5y = -2x + 18 or 5y + 2x - 18 = 0
2y = 5x + 4 (4, 2) y = 5x/2 + 4 comparing with y = mx + e m = 5/2 Since they are perpendicular m1m2 = -1 m2 = −1/m1 = -1 5/2 = -1 x 2/5 The equator of the line is thus y = mn + c (4, 2) 2 = -2/5(4) + c 2/1 + 8/5 = c c = 18/5 y = -2/5x + 18/5 5y = -2x + 18 or 5y + 2x - 18 = 0THIS WEEK's
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