2010
Mathematics
67ca00ce0c643c71d77dee1f
Find ∫(sin x + 2)dx
A.
cos x + x2 + K
B.
cos x 2x + K
C.
-cos x + x2 + K
D.
-cos x + 2x + K
Correct Answer: -cos x + 2x + K
Explanation
∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx = -cos χ + 2χ + K
∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx = -cos χ + 2χ + KTHIS WEEK's
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