passpadi

2010

Mathematics

JAMB

Find ∫(sin x + 2)dx

A.

cos x + x2 + K

B.

cos x 2x + K

C.

-cos x + x2 + K

D.

-cos x + 2x + K

Correct Answer: -cos x + 2x + K

Explanation

∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx = -cos χ + 2χ + K

∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx = -cos χ + 2χ + K
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