2010
Mathematics
JAMB
In how many ways can a committee of 2 women and 3 men be chosen from 6 men and 5 women?
A.
100
B.
200
C.
30
D.
50
Correct Answer: 200
Explanation
A committee of 2 women and 3 men can be chosen from 6 men and 5 women, in 5C2 x 6C3 ways = 5!/(5−2)!2! × 6!/(6−3)!3! = 5!/3!2! × 6!/3×3! = 5×4×3!/3!×2! × 6×5×4×3!/3!×3! = 5×4/1×2 × 6×5×4/1×2×3 = 10 x (6×20)/6 = 200
A committee of 2 women and 3 men can be chosen from 6 men and 5 women, in 5C2 x 6C3 ways = 5!/(5−2)!2! × 6!/(6−3)!3! = 5!/3!2! × 6!/3×3! = 5×4×3!/3!×2! × 6×5×4×3!/3!×3! = 5×4/1×2 × 6×5×4/1×2×3 = 10 x (6×20)/6 = 200THIS WEEK's
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