2010
Mathematics
JAMB
What is the locus of point that is equidistant from points P(1,3) and Q(3,5)?
A.
y = -χ + 6
B.
y = -χ - 6
C.
y = χ + 6
D.
y = χ - 6
Correct Answer: y = -χ + 6
Explanation
Locus of a point equidistant from two fixed points is the perpendicular bisector of the straight line joining the points Gradients of PQ = (5-3 / 3-1) = 2/2 = 1 Gradient bisector = -1 Equation of perpendicular bisector y - y1 = m(χ - χ1 y - 4 = -χ + 2 y = -χ + 6
Locus of a point equidistant from two fixed points is the perpendicular bisector of the straight line joining the points Gradients of PQ = (5-3 / 3-1) = 2/2 = 1 Gradient bisector = -1 Equation of perpendicular bisector y - y1 = m(χ - χ1 y - 4 = -χ + 2 y = -χ + 6THIS WEEK's
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