2010
Mathematics
67ca00ce0c643c71d77dee1f
A student measures a piece of rope and found that it was 1.26m long. If the actual length of the rope was 1.25m, what was the percentage error in the measurement?
A.
0.25%
B.
0.01%
C.
0.80%
D.
0.40%
Correct Answer: 0.80%
Explanation
Actual length of rope = 1.25m Measured length of rope = 1.26m error = (1.26 - 1.25)m - 0.01m Percentage error = error/actual length x 100% = 0.01/1.25 x 100% = 0.8%
Actual length of rope = 1.25m Measured length of rope = 1.26m error = (1.26 - 1.25)m - 0.01m Percentage error = error/actual length x 100% = 0.01/1.25 x 100% = 0.8%THIS WEEK's
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