passpadi

2010

Mathematics

JAMB

Find the equation of a line parallel to y = -4x + 2 passing through (2,3)

A.

y + 4x + 11 = 0

B.

y - 4x - 11 = 0

C.

y + 4x - 11 = 0

D.

y - 4x + 11 = 0

Correct Answer: y + 4x - 11 = 0

Explanation

By comparing y = mx + c with y = -4x + 2, the gradient of y = -4x + 2 is m1 = -4 let the gradient of the line parallel to the given line be m2, then, m2 = m1 = -4 (condition for parallelism) using, y - y1 = m2(x - x1) Hence the equation of the parallel line is y - 3 = -4(x-2) y - 3 = -4 x + 8 y + 4x = 8 + 3 y + 4x = 11 y + 4x - 11 = 0

By comparing y = mx + c with y = -4x + 2, the gradient of y = -4x + 2 is m1 = -4 let the gradient of the line parallel to the given line be m2, then, m2 = m1 = -4 (condition for parallelism) using, y - y1 = m2(x - x1) Hence the equation of the parallel line is y - 3 = -4(x-2) y - 3 = -4 x + 8 y + 4x = 8 + 3 y + 4x = 11 y + 4x - 11 = 0
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