2009
Mathematics
JAMB
If P = [] evaluate x if |P| = -10
A.
-5
B.
-2
C.
2
D.
5
Correct Answer: 5
Explanation
(x+3)(x-1) - {(x+1)(x+2)} = -10 x2 - x + 3x - 3 - {x2 + 2x + x + 2} = -10 x2 + 2x - 3 - {x2 + 3x + 2} = -10 -x - 5 = -10 -5 + 10 = x 5 = x ∴x = 5
(x+3)(x-1) - {(x+1)(x+2)} = -10 x2 - x + 3x - 3 - {x2 + 2x + x + 2} = -10 x2 + 2x - 3 - {x2 + 3x + 2} = -10 -x - 5 = -10 -5 + 10 = x 5 = x ∴x = 5THIS WEEK's
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