passpadi

2009

Mathematics

JAMB

Find the locus of a particle which moves in the first quadrant so that it is equidistant from the lines x = 0 and y = 0 (where k is a constant)?

A.

x + y = 0

B.

x - y = 0

C.

x + y + k = 0

D.

x - y - k = 0

Correct Answer: x - y = 0

Explanation

Locus of a particle which moves in the first quadrant so that it is equidistant from the lines X = 0 and Y = 0 are the x and y axes as the lines bisecting the angle between x and y axes.

Locus of a particle which moves in the first quadrant so that it is equidistant from the lines X = 0 and Y = 0 are the x and y axes as the lines bisecting the angle between x and y axes.
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