2009
Mathematics
JAMB
The sum of the first n terms of the arithmetic progression 5, 11, 17, 23, 29, 35, ... is?
A.
n(3n - 0.5)
B.
n(3n + 2)
C.
n(3n + 2.5)
D.
n(3n + 5)
Correct Answer: n(3n + 2)
Explanation
a = 5, d = 6, n = n Sn = n/2(2a + (n-1)d) = n/2(2(5) + (n-1)6) = n/2(10 + 6n-6) = n/2(6n+4) = 6n2/2 + 4n/2 = 32 + 2n = n(3n + 2)
a = 5, d = 6, n = n Sn = n/2(2a + (n-1)d) = n/2(2(5) + (n-1)6) = n/2(10 + 6n-6) = n/2(6n+4) = 6n2/2 + 4n/2 = 32 + 2n = n(3n + 2)THIS WEEK's
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