2009
Mathematics
JAMB
Find the acute angle between the straight lines y = x and y = √3x
A.
15°
B.
30°
C.
45°
D.
60°
Correct Answer: 15°
Explanation
y = x, Gradient (m1) = 1 y = √3x gradient (m2) = √3 tanθ = (m2 -m1 )/(1+m2 m1 ). tanθ = (√3-1)/(1+√3×1)=(1.73-1)/(1+1.73)=0.73/2.73 = 0.268. θ = Tan-1 (0.268) = 15°
y = x, Gradient (m1) = 1 y = √3x gradient (m2) = √3 tanθ = (m2 -m1 )/(1+m2 m1 ). tanθ = (√3-1)/(1+√3×1)=(1.73-1)/(1+1.73)=0.73/2.73 = 0.268. θ = Tan-1 (0.268) = 15°THIS WEEK's
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