passpadi

2008

Mathematics

JAMB

Find the minimum value of the function y = x(1+x)

A.

-1/4

B.

-1/2

C.

1/4

D.

1/2

Correct Answer: -1/4

Explanation

y = x(1+x) = x + x2 dy/dx = 1 + 2x As dy/dy → 0 1 + 2x = 0 2x = -1 X = -1/2 Y = x(1+x) = -1/2(1 - 1/2) at x = -1/2 = -1/2(1/2) = -1/4

y = x(1+x) = x + x2 dy/dx = 1 + 2x As dy/dy → 0 1 + 2x = 0 2x = -1 X = -1/2 Y = x(1+x) = -1/2(1 - 1/2) at x = -1/2 = -1/2(1/2) = -1/4
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