passpadi

2008

Mathematics

JAMB

Find the gradient of a line which is perpendicular to the line with the equation 3x + 2y + 1 = 0

A.

3/2

B.

2/3

C.

-2/3

D.

-3/2

Correct Answer: 2/3

Explanation

3X + 2Y + 1 = 0 2Y = -3X - 1 −3/2X−1/2 Gradient of 3X + 2Y +1 = 0 is -3/2 Gradient of a line perpendicular to 3X + 2Y + 1 = 0 =−1÷3/2 = −1 × −2/3 =2/3

3X + 2Y + 1 = 0 2Y = -3X - 1 −3/2X−1/2 Gradient of 3X + 2Y +1 = 0 is -3/2 Gradient of a line perpendicular to 3X + 2Y + 1 = 0 =−1÷3/2 = −1 × −2/3 =2/3
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