2007
Mathematics
JAMB
Find the locus of point equidistant from two straight lines y - 5 = 0 and y - 3 = 0
A.
y - 2 = 0
B.
y - 4 = 0
C.
y - 1 = 0
D.
y - 3 = 0
Correct Answer: y - 4 = 0
Explanation
Locus of point P equidistant from y - 5 = 0 and y - 3 = 0 is y = 4 i.e y - 4 = 0
Locus of point P equidistant from y - 5 = 0 and y - 3 = 0 is y = 4 i.e y - 4 = 0THIS WEEK's
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