2007
Mathematics
JAMB
Determine the value of ∫0(π/2)(-2cosx)dx
A.
(π/2)
B.
-1/2
C.
-3
D.
-3/2
Correct Answer: (π/2)
Explanation
∫0(π/2)(-2cosx)dx=[-2sinx+c]0(π/2)=(-2sin π/2 + c + 2sin0 - c) = -2sin90 + c + 2sin0 - c.= -2(1) + 2(0) = -2
∫0(π/2)(-2cosx)dx=[-2sinx+c]0(π/2)=(-2sin π/2 + c + 2sin0 - c) = -2sin90 + c + 2sin0 - c.= -2(1) + 2(0) = -2THIS WEEK's
Latest Articles
Top-Scorer Okoro Uchechukwu Solomon Reveals How He Scored 337 in JAMB
by samuel olalekan adeyemi
Bouncing Back: How Samuel Isaac Overcame Setbacks to Score 265 in JAMB and What He Learned
by samuel olalekan adeyemi
Managing Stress During Exams: Practical Tips for Students
by samuel olalekan adeyemi
