2007

Mathematics

JAMB

Integrate (x²-√x)/x with respect to x

A. x²/2-2√x+K

B. (2(x²-x))/3x+K

C. x²/2-√x+K

D. ((x²-x))/3x+K

Correct Answer: x²/2-2√x+K

Explanation

SOLUTION: $\int \frac{x^{2} - \sqrt{x}}{x} = \int \frac{x^{2}}{x} - \frac{x^{\frac{1}{2}}}{x} \int x - x^{\frac{- 1}{2}} = (\frac{1}{2}) x^{2} - \frac{x^{\frac{1}{2}}}{\frac{1}{2}} + K = \frac{x^{2}}{2} - 2 x^{\frac{1}{2}} + K = \frac{x^{2}}{2} - 2 \sqrt{x} + K$

SOLUTION:

\int \frac{x^{2} - \sqrt{x}}{x} = \int \frac{x^{2}}{x} - \frac{x^{\frac{1}{2}}}{x} \int x - x^{\frac{- 1}{2}} = (\frac{1}{2}) x^{2} - \frac{x^{\frac{1}{2}}}{\frac{1}{2}} + K = \frac{x^{2}}{2} - 2 x^{\frac{1}{2}} + K = \frac{x^{2}}{2} - 2 \sqrt{x} + K

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2007

Mathematics

JAMB

Integrate (x2-√x)/x with respect to x

A.

x2/2-2√x+K

B.

(2(x2-x))/3x+K

C.

x2/2-√x+K

D.

((x2-x))/3x+K

Correct Answer: x2/2-2√x+K

Explanation

SOLUTION: ∫ x 2 − x x = ∫ x 2 x − x 1 2 x ∫ x − x − 1 2 = ( 1 2 ) x 2 − x 1 2 1 2 + K = x 2 2 − 2 x 1 2 + K = x 2 2 − 2 x + K

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by samuel olalekan adeyemi

Bouncing Back: How Samuel Isaac Overcame Setbacks to Score 265 in JAMB and What He Learned

by samuel olalekan adeyemi

Managing Stress During Exams: Practical Tips for Students

by samuel olalekan adeyemi

Unlocking Learning Potential: The Power of Self-Quizzing Techniques for Students

by dahmmy

Integrate (x²-√x)/x with respect to x

x²/2-2√x+K

(2(x²-x))/3x+K

x²/2-√x+K

((x²-x))/3x+K

Correct Answer: x²/2-2√x+K

SOLUTION: $\int \frac{x^{2} - \sqrt{x}}{x} = \int \frac{x^{2}}{x} - \frac{x^{\frac{1}{2}}}{x} \int x - x^{\frac{- 1}{2}} = (\frac{1}{2}) x^{2} - \frac{x^{\frac{1}{2}}}{\frac{1}{2}} + K = \frac{x^{2}}{2} - 2 x^{\frac{1}{2}} + K = \frac{x^{2}}{2} - 2 \sqrt{x} + K$