2007

Mathematics

JAMB

A man 40 m from the foot of a tower observes the angle of elevation of the tower to be 30°. Determine the height of the tower.

A.

(40√3)/3 m

B.

20 m

C.

40√3 m

D.

40 m

Correct Answer: (40√3)/3 m

Explanation

SOLUTION: $T a n 30 = \frac{h}{40} \frac{1}{\sqrt{3}} = \frac{h}{40} h \sqrt{3} = 40 h = \frac{40}{\sqrt{3}} h = \frac{40}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} h = \frac{40 \sqrt{3}}{3}$

SOLUTION:

T a n 30 = \frac{h}{40} \frac{1}{\sqrt{3}} = \frac{h}{40} h \sqrt{3} = 40 h = \frac{40}{\sqrt{3}} h = \frac{40}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} h = \frac{40 \sqrt{3}}{3}

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