In a basket, there are 6 grapes, 11 bananas and 13 oranges. If one fruit is chosen at random. What is the probability that the fruit is either a grape or a banana
A.
6/30
B.
5/30
C.
17/30
D.
11/30
Correct Answer: 17/30
Explanation
Number of grapes = 6
Number of banana = 11
Number of oranges = 13
Total = 30
P(Grape) = 6/30, P(Banana) = 11/30
P(Orange) = 13/30
∴P(Either grape or banana) = 6/30 + 11/30
= 17/30
Number of grapes = 6
Number of banana = 11
Number of oranges = 13
Total = 30
P(Grape) = 6/30, P(Banana) = 11/30
P(Orange) = 13/30
∴P(Either grape or banana) = 6/30 + 11/30
= 17/30