2006
Mathematics
67ca00ce0c643c71d77dee1f
The sum of the first n positive integers is
A.
1/2 n(n-1)
B.
n(n+1)
C.
n(n-1)
D.
1/2 n(n-1)
Correct Answer: 1/2 n(n-1)
Explanation
Let the positive integers be 1, 2, ,3, 4, .....n ∴ a = 1, d = 1 and n = n Sn = n/2(2a + (n-1)d) = n/2 (2 + n – 1) = 1/2n(n + 1)
Let the positive integers be 1, 2, ,3, 4, .....n ∴ a = 1, d = 1 and n = n Sn = n/2(2a + (n-1)d) = n/2 (2 + n – 1) = 1/2n(n + 1)THIS WEEK's
Latest Articles
Top-Scorer Okoro Uchechukwu Solomon Reveals How He Scored 337 in JAMB
by samuel olalekan adeyemi
Bouncing Back: How Samuel Isaac Overcame Setbacks to Score 265 in JAMB and What He Learned
by samuel olalekan adeyemi
Managing Stress During Exams: Practical Tips for Students
by samuel olalekan adeyemi
