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2006
Mathematics
JAMB
Evaluate ∫
-4
0
(1-2x)dx
A.
-16
B.
-20
C.
20
D.
10
Correct Answer:
20
Explanation
∫
-4
0
(1-2x)dx=[x-x
2
]
-4
0
"\=" (0-0+C)-(-4(-4)
2
+C)=C-(-4-16+C)=C-(-20+C)=C+20-C=20
∫
-4
0
(1-2x)dx=[x-x
2
]
-4
0
"\=" (0-0+C)-(-4(-4)
2
+C)=C-(-4-16+C)=C-(-20+C)=C+20-C=20
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