passpadi

2006

Mathematics

JAMB

Evaluate ∫-4 0(1-2x)dx

A.

-16

B.

-20

C.

20

D.

10

Correct Answer: 20

Explanation

-4 0(1-2x)dx=[x-x2 ]-40 "\=" (0-0+C)-(-4(-4)2+C)=C-(-4-16+C)=C-(-20+C)=C+20-C=20

-4 0(1-2x)dx=[x-x2 ]-40 "\=" (0-0+C)-(-4(-4)2+C)=C-(-4-16+C)=C-(-20+C)=C+20-C=20
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