2006
Mathematics
JAMB
The gradient of a curve is 2x + 7 and the curve passes through point (2, 0). find the equation of the curve.
A.
y = x2 + 7x + 9
B.
y = x2 + 7x - 18
C.
y = x2 + 7x + 18
D.
y = x2 + 14x + 11
Correct Answer: y = x2 + 7x - 18
Explanation
dy/dx = 2x + 7 y = ∫2x + 7 y = x2 + 7x + C at (2,0) 0 = 22 + 7(2) + C 0 = 4 + 14 + C 0 = 18 + C C = -18 ∴ The equation is y = x2 + 7x - 18
dy/dx = 2x + 7 y = ∫2x + 7 y = x2 + 7x + C at (2,0) 0 = 22 + 7(2) + C 0 = 4 + 14 + C 0 = 18 + C C = -18 ∴ The equation is y = x2 + 7x - 18THIS WEEK's
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